Speed shrinks time

Here I'm going to present only the mathematical aspects on the subject. You can read the full story on my blog.
Distance contraction is represented in the formula:

(1)

\begin{align} L' = \frac{L}{\gamma\left(v\right)} \end{align}

Where L is the distance and $\gamma(v)$ is the Lorentz factor for some velocity v
Time, which is t = distance / velocity is equivalent to $T' = L' / (rc)$, where $r = v / c$. Since $1 / \gamma = \epsilon = \sqrt{1 - v^2 / c^2} = \sqrt{1 - r^2}$, we get: $T' = \frac{L}{rc}\sqrt{1 - r^2}$. We consider c = 1, as in 1 light-year / year, so finnaly:

(2)

\begin{align} T' = d\sqrt{\frac{1}{r^2} - 1} \end{align}

It is also true that the time ratio, $t / T' = \gamma$, and thus $T' = t / \gamma$
At any rate, the formula for T ' is used to calculate the relative time a space ship will need to travel a distance of d with a speed rc, r < 1
In the case of Faztzorg-9800, d = 100000 light years, and r = 0.98, the Lorentz factor is about 5.

Also, used in the blog post is the relativistic mass, given by $M = m \gamma(v)$, for any non-zero mass object moving at a velocity v